Advertisements
Advertisements
प्रश्न
Find the value of n, when:
`12^-5xx12^(2"n"+1)=12^13÷12^7`
बेरीज
Advertisements
उत्तर
`12^-5xx12^(2"n"+1)=12^13÷12^7`
`12^(-5+2"n"+1)=12^13/12^7`
`12^(2"n"-4)=12^(13-7)`
`12^(2"n"-4)=12^6`
Comparing both sides,we get
`2"n"-4=6`
`⇒2"n"=6+4`
`⇒2"n"=10`
`⇒"n"=5`
shaalaa.com
More About Exponents
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Compute:
`1^8xx3^0xx5^3xx2^2`
Compute:
`(2/3)^(-4)xx(27/8)^-2`
Compute:
`(56/28)^0÷(2/5)^3xx16/25`
Compute:
`9^0xx4^-1÷2^-4`
Simplify:
`8^(4/3)+25^(3/2)-(1/27)^(-2/3)`
Evaluate:
`8^0+4^0+2^0`
Simplify:
`(36"x"^2)^(1/2)`
Simplify:
`(125"x"^-3)^(1/3)`
Simplify:
`(-2"x"^(2/3)"y"^(-3/2))^6`
Simplify and express as positive indice:
(xy)(m-n).(yz)(n-l).(zx)(l-m)
