Advertisements
Advertisements
प्रश्न
Compute:
`(27)^(2/3)÷(81/16)^(-1/4)`
योग
Advertisements
उत्तर
`(27)^(2/3) ÷ (81/16)^(-1/4) = (3^3)^(2/3) ÷ (3^4/2^4)^(-1/4)`
`= 3^(3 xx 2/3) ÷ 3^(-1/4 xx 4)/2^(-1/4 xx 4) = 3^2 ÷ 3^-1/2^-1`
`= 3^2 xx 2^-1/3^-1`
`= 3^(2 + 1) xx 2^-1 = 3^3 xx 1/2^ + 1`
`= (3 xx 3 xx 3)/2 = 27/2 = 13 1/2`
shaalaa.com
More About Exponents
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Compute:
`(4^7)^2xx(4^-3)^4`
Compute:
`(12)^-2xx3^3`
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`(625)^(-3/4)`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Simplify:
`8^(4/3)+25^(3/2)-(1/27)^(-2/3)`
Simplify:
`(2^-3-2^-4)(2^-3+2^-4)`
Simplify:
`15"y"^8÷3"y"^3`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
