Advertisements
Advertisements
प्रश्न
Compute:
`(-3)^4-(root(4)(3))^0xx(-2)^5÷(64)^(2/3)`
योग
Advertisements
उत्तर
`(-3)^4-(root(4)(3))^0xx(-2)^5÷(64)^(2/3)`
`=(-3xx-3xx-3xx-3)-1xx-2xx-2xx-2xx-2xx-2÷(2^6)^(2/3)`
Note : `(root(4)3)^0=1`
`=3^4+2^5÷2^(6xx2/3)`
`=3^4+2^5÷2^4=3^4+2^5/2^4`
`=3^4+2^(5-4)=3^4+2=3xx3xx3xx3+2`
`=81+2=83`
shaalaa.com
More About Exponents
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Compute:
`(-5)^4xx(-5)^6÷(-5)^9`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Evaluate:
`(-5)^0`
Evaluate:
`9^0+9^-1-9^-2+9^(1/2)-9^(-1/2)`
Simplify:
`"x"^10"y"^6÷"x"^3"y"^-2`
Simplify:
`(2"x"^2"y"^-3)^-2`
Simplify and express as positive indice:
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
Evaluate:
`(x^(5+n)(x^2)^(3n+1))/x^(7n-2)`
Prove that:
`("m"+"n")^-1("m"^-1+"n"^-1)=("m""n")^-1`
Find the value of n, when:
`12^-5xx12^(2"n"+1)=12^13÷12^7`
