Advertisements
Advertisements
प्रश्न
Simplify:
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1)`
Advertisements
उत्तर
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1))`
Given expression`=("a"^(2"n"+3)."a"^((2"n"^2+4"n"+"n"+2)))/("a"^(6"n"+3)."a"^(2"n"^2+"n"`
`="a"^(2"n"+3+2"n"^2+5"n"+2)/"a"^(6"n"+3+2"n"^2+"n")`
`="a"^(2"n"^2+7"n"+5)/"a"^(2"n"^2+7"n"+3`
`= a^(2n^2 +7n + 5 - 2n^2 - 7n - 3 )`
`= a^2`
APPEARS IN
संबंधित प्रश्न
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`9^0xx4^-1÷2^-4`
Compute:
`(125)^(-2/3)÷(8)^(2/3)`
Simplify:
`8^(4/3)+25^(3/2)-(1/27)^(-2/3)`
Evaluate:
`8^0+4^0+2^0`
Evaluate:
`9^0+9^-1-9^-2+9^(1/2)-9^(-1/2)`
Simplify:
`("a"^5"b"^2)/("a"^2"b"^-3`
Simplify and express as positive indice:
`("a"^(-2)"b")^(1/2)xx("a""b"^-3)^(1/3)`
Prove that:
`("m"+"n")^-1("m"^-1+"n"^-1)=("m""n")^-1`
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
