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प्रश्न
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
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उत्तर
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
Given expression`=("x"^(2"n"+7)."x"^(6"n"+4))/"x"^(8"n"+12`
`="x"^(2"n"+7+6"n"+4)/"x"^(8"n"+12)="x"^(8"n"+11)/"x"^(8"n"+12`
`="x"^(8"n"+11-8"n"-12)="x"^-1`
`=1/"x"`
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संबंधित प्रश्न
Compute:
`(-1/3)^4÷(-1/3)^8xx(-1/3)^5`
Compute:
`9^0xx4^-1÷2^-4`
Compute:
`(-3)^4-(root(4)(3))^0xx(-2)^5÷(64)^(2/3)`
Simplify:
`[(64)^-2]^-3÷[{(-8)^2}^3]^2`
Evaluate:
`8^0+4^0+2^0`
Simplify and express as positive indice:
(xy)(m-n).(yz)(n-l).(zx)(l-m)
Show that:
`(("x"^"a")/"x"^(-"b"))^("a"-"b").(("x"^"b")/"x"^(-"c"))^("b"-"c").(("x"^"c")/("x"^(-"a")))^("c"-"a")=1`
Prove that:
`("m"+"n")^-1("m"^-1+"n"^-1)=("m""n")^-1`
Prove that:
`((x^a)/x^b)^(1/(ab))((x^b)/x^c)^(1/(bc))(x^c/x^a)^(1/(ca))=1`
Simplify:
`("a"^(2"n"+3)."a"^((2"n"+1)("n"+2)))/(("a"^3)^(2"n"+1)."a"^("n"(2"n"+1)`
