Advertisements
Advertisements
प्रश्न
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
योग
Advertisements
उत्तर
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
Given expression`=("x"^(2"n"+7)."x"^(6"n"+4))/"x"^(8"n"+12`
`="x"^(2"n"+7+6"n"+4)/"x"^(8"n"+12)="x"^(8"n"+11)/"x"^(8"n"+12`
`="x"^(8"n"+11-8"n"-12)="x"^-1`
`=1/"x"`
shaalaa.com
More About Exponents
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Compute:
`(2/3)^(-4)xx(27/8)^-2`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Evaluate:
`(-5)^0`
Simplify:
`15"y"^8÷3"y"^3`
Simplify:
`(36"x"^2)^(1/2)`
Simplify:
`(125"x"^-3)^(1/3)`
Simplify:
`(2"x"^2"y"^-3)^-2`
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
Evaluate:
`("a"^(2"n"+1)xx"a"^((2"n"+1)(2"n"-1)))/("a"^("n"(4"n"-1))xx("a"^2)^(2"n"+3)`
Find the value of n, when:
`12^-5xx12^(2"n"+1)=12^13÷12^7`
