Advertisements
Advertisements
प्रश्न
Simplify:
`(27"x"^-3"y"^6)^(2/3)`
बेरीज
Advertisements
उत्तर
`(27"x"^-3"y"^6)^(2/3)=(27)^(2/3)."x"^(-3xx2/3)."y"^(6xx2/3`
`=(3xx3xx3)^(2/3)."x"^-2."y"^4`
`=[(3xx3xx3)^(1/3)]^2."x"^-2."y"^4`
`=3^2."x"^-2"y"^4`
`=9"x"^-2"y"^4`
`=(9"y"^4)/"x"^2=9"x"^-2"y"^4`
shaalaa.com
More About Exponents
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Compute:
`(2^-9÷2^-11)^3`
Compute:
`(243)^(2/5)÷(32)^(-2/5)`
Simplify:
`8^(4/3)+25^(3/2)-(1/27)^(-2/3)`
Simplify:
`("a"^5"b"^2)/("a"^2"b"^-3`
Simplify:
`(2"x"^2"y"^-3)^-2`
Simplify:
`(-2"x"^(2/3)"y"^(-3/2))^6`
Prove that:
`("m"+"n")^-1("m"^-1+"n"^-1)=("m""n")^-1`
Find the value of n, when:
`12^-5xx12^(2"n"+1)=12^13÷12^7`
Find the value of n, when:
`("a"^(2"n"-3)xx("a"^2)^("n"+1))/(("a"^4)^-3)=("a"^3)^3÷("a"^6)^-3`
Simplify:
`("x"^(2"n"+7).("x"^2)^(3"n"+2))/"x"^(4(2"n"+3)`
