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Question
Show that the combined equation of pair of lines passing through the origin is a homogeneous equation of degree 2 in x and y. Hence find the combined equation of the lines 2x + 3y = 0 and x − 2y = 0
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Solution

Let a1x + b1y = 0 and a2x + b2y = 0 be a pair of lines passing through the origin.
∴ Their combined equation is (a1x + b1y)(a2x + b2y) = 0
∴ a1a2x2 + a1b2xy + b1a2xy + b1b2y2 = 0
∴ (a1a2)x2 + (a1b2 + a2b1)xy + (b1b2)y2 = 0
In this if we put a1a2 = a, a1b2 + a2b1 = 2h, b1b2 = b, We get ax2 + 2hxy + by2 = 0 which is a homogeneous equation of degree 2 in x and y.
Now, on comparing 2x + 3y = 0 and x − 2y = 0 with a1x + b1y = 0 and a2x + b2y = 0,
we get a1 = 2, b1 = 3, a2 = 1 and b2 = −2
Substituting in equation (i), we get
2(1)x2 + [2(−2) + 1(3)]xy + 3(−2)y2 = 0
i.e., 2x2 − xy − 6y2 = 0,
Which is the required combined equation.
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