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Prove that the combined of the pair of lines passing through the origin and perpendicular to the lines ax2 + 2hxy + by2 = 0 is bx2 - 2hxy + ay2 = 0. - Mathematics and Statistics

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Question

Prove that the combined of the pair of lines passing through the origin and perpendicular to the lines ax2 + 2hxy + by2 = 0 is bx2 - 2hxy + ay2 = 0.

Sum
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Solution

Let m1 and m2 be the slopes of the lines represented by ax2 + 2hxy + by2 = 0.

∴ m1 + m2 = `(- 2"h")/"b"`  and m1m2 = `"a"/"b"`  ....(1)

Now, the required lines are perpendicular to these lines. 

∴ their slopes are `- 1/"m"_1` and `- 1/"m"_2`

Since these lines are passing through the origin, their separate equations are

y = `- 1/"m"_1`x   and  y = `- 1/"m"_2`x

i.e. m1y = - x and m2y = - x

i.e. x + m1y = 0   and  x + m2y = 0

∴ their combined equation is

(x + m1y)(x + m2y) = 0

∴ x2 + (m1 + m2)xy + m1m2y2 = 0

∴ `"x"^2 (-"2h")/"b" "x" + "a"/"b" "y"^2 = 0`   ...[By(1)]

∴ bx2 - 2hxy + ay2 = 0

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Chapter 4: Pair of Straight Lines - Miscellaneous Exercise 4 [Page 132]

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Balbharati Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 4 Pair of Straight Lines
Miscellaneous Exercise 4 | Q 25 | Page 132

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