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Select the correct option from the given alternatives: The system 3x – y + 4z = 3, x + 2y –3z = –2 and 6x + 5y + λz = –3 has at least one Solution when

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Question

Select the correct option from the given alternatives:

The system 3x – y + 4z = 3, x + 2y – 3z = –2 and 6x + 5y + λz = –3 has at least one Solution when

Options

  • λ = –5

  • λ = 5

  • λ = 3

  • λ = –13

MCQ
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Solution

λ = –5

Explanation:

The given system of equations will have more than one solution if

`|(3, -1, 4),(1, 2, -3),(6, 5, lamda)|` = 0

Applying R3 → R3 – (R1 + 3R2), we get

`|(3, -1, 4),(1, 2, -3),(0, 0, lambda + 5)|` = 0

∴ 3[2(λ + 5) – 0] – (–1) (λ + 5 – 0) + 4(0 – 0) = 0

∴ 7λ + 35 = 0

∴ λ = `-35/7`

= – 5

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Chapter 4: Determinants and Matrices - Miscellaneous Exercise 4(A) [Page 76]

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Balbharati Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
Chapter 4 Determinants and Matrices
Miscellaneous Exercise 4(A) | Q I. (6) | Page 76

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