English

Evaluate: |x2-x+1x-1x+1x+1|

Advertisements
Advertisements

Question

Evaluate: `|(x^2 - x + 1, x - 1),(x + 1, x + 1)|`

Sum
Advertisements

Solution

We have, `|(x^2 - x + 1, x - 1),(x + 1, x + 1)|`

[Applying C1 → C1 – C2]

= `|(x^2 - 2x + 2, x - 1),(0, x + 1)|`

= (x2 – 2x + 2) · (x + 1) – (x – 1) · 0

= x3 – 2x2 + 2x + x2 – 2x + 2

= x3 – x2 + 2

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Determinants - Exercise [Page 77]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 4 Determinants
Exercise | Q 1 | Page 77
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×