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प्रश्न
Evaluate: `|(x^2 - x + 1, x - 1),(x + 1, x + 1)|`
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उत्तर
We have, `|(x^2 - x + 1, x - 1),(x + 1, x + 1)|`
[Applying C1 → C1 – C2]
= `|(x^2 - 2x + 2, x - 1),(0, x + 1)|`
= (x2 – 2x + 2) · (x + 1) – (x – 1) · 0
= x3 – 2x2 + 2x + x2 – 2x + 2
= x3 – x2 + 2
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