English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Predict the reagent or the product in the following reaction sequence.

Advertisements
Advertisements

Question

Predict the reagent or the product in the following reaction sequence.

Long Answer
Advertisements

Solution

1. \[\ce{Sn/HCl or Fe/HCl}\]

2. 

3. \[\ce{H2O/H+}\]

4.  

5. \[\ce{H3PO2/H2O}\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 13: Amines - Multiple Choice Questions (Type - I) [Page 193]

APPEARS IN

NCERT Exemplar Chemistry Exemplar [English] Class 12
Chapter 13 Amines
Multiple Choice Questions (Type - I) | Q 77 | Page 193

RELATED QUESTIONS

Illustrate the following reaction giving suitable example in each case: Diazotisation

 


Write equations of the following reactions:
Acetylation of aniline


Arenium ion involved in the bromination of aniline is:

(i)

(ii)

(iii)

(iv)


Why is benzene diazonium chloride not stored and is used immediately after its preparation?


Why does acetylation of –NH2 group of aniline reduce its activating effect?


Predict the product of reaction of aniline with bromine in non-polar solvent such as \[\ce{CS2}\].


Which of the following statement about primary amines is false?


In order to distinguish between C2H5NHz and C6H5NHz, which of the following reagents is useful?


Which of the following is true characteristic feature of aniline?


Which of the following is the most stable diazonium salt?


Aniline dissolved in dilute HCl is reacted with sodium nitrate at 0 °C. This solution was added dropwise to a solution containing equimolar mixture of aniline and phenol in dil. HCl. The structure of the major product is:


Identify A and B for the following reaction:

What are polymers?


How will the following be converted? (Give chemical equation)

Aniline to benzene diazonium chloride.


Given below are two statements:

Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.

Statement II: Insertion of iodine into the benzene ring is difficult and hence, iodobenzene is prepared through the reaction of benzenediazonium salt with KI.

In the light of the above statements, choose the most appropriate answer from the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×