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Question
Obtain the equivalent capacitance of the network shown in the figure. For a 300 V supply, determine the charge on each capacitor.
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Solution
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The equivalent capacitance = `200/3` pF
charge on C4 = `200/3 xx 10^-12 xx 300 = 2 xx 10^-8` C,
the potential difference across C4 = `(200 xx 10^-12 xx 300)/(3 xx 100 xx 10^-12)` = 200 V
potential difference across C1 = 300 - 200 = 100 V
charge on C1 = 100 × 10-12 × 100 = 1 × 10-8 C
potential difference across C2 and C3 series combination = 100 V
potential difference across C2 and C3 each = 50 V
charge on C2 and C3 each = 200 × 10-12 × 50 = 1 × 10-8 C
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