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Question
Match the species given in Column I with the hybridisation given in Column II.
| Column I | Column II |
| (i) Boron in [B(OH)4]– | (a) sp2 |
| (ii) Aluminium in [Al(H2O)6]3+ | (b) sp3 |
| (iii) Boron in B2H6 | (c) sp3d2 |
| (iv) Carbon in Buckminsterfullerene | |
| (v) Silicon in \[\ce{SiO^{4-}4}\] | |
| (vi) Germanium in [GeCl6]2– |
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Solution
| Column I | Column II |
| (i) Boron in [B(OH)4]– | (b) sp3 |
| (ii) Aluminium in [Al(H2O)6]3+ | (c) sp3d2 |
| (iii) Boron in B2H6 | (b) sp3 |
| (iv) Carbon in Buckminsterfullerene | (a) sp2 |
| (v) Silicon in \[\ce{SiO^{4-}4}\] | (b) sp3 |
| (vi) Germanium in [GeCl6]2– | (c) sp3d2 |
Explanation:
(i) Boron in [B(OH)4]– is sp3
(ii) Aluminium in [Al(H20)6]3+ is sp3d2 hybridized
(iii) Boron in B2H6 is sp3
(iv) Carbon in Buckminsterfullerene sp2 is hybridised.
(v) Silicon in \[\ce{SiO^{4-}4}\] is sp3
(vi) Germanium in [GeCl6]2- is sp3d2
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