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Match the species given in Column I with the hybridisation given in Column II. Column I Column II (i) Boron in [B(OH)4]– (a) sp2 (ii) Aluminium in [Al(H2O)6]3+ (b) sp3 (iii) Boron in B2H6 (c) sp3d2

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प्रश्न

Match the species given in Column I with the hybridisation given in Column II.

Column I Column II
(i) Boron in [B(OH)4] (a) sp2
(ii) Aluminium in [Al(H2O)6]3+ (b) sp3
(iii) Boron in B2H6 (c) sp3d2
(iv) Carbon in Buckminsterfullerene  
(v) Silicon in \[\ce{SiO^{4-}4}\]  
(vi) Germanium in [GeCl6]2–  
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उत्तर

Column I Column II
(i) Boron in [B(OH)4] (b) sp3
(ii) Aluminium in [Al(H2O)6]3+ (c) sp3d2
(iii) Boron in B2H6 (b) sp3
(iv) Carbon in Buckminsterfullerene (a) sp2
(v) Silicon in \[\ce{SiO^{4-}4}\] (b) sp3
(vi) Germanium in [GeCl6]2– (c) sp3d2

Explanation:

(i) Boron in [B(OH)4] is sp3

(ii) Aluminium in [Al(H20)6]3+ is sp3d2 hybridized

(iii) Boron in B2H6 is sp3

(iv) Carbon in Buckminsterfullerene sp2 is hybridised.

(v) Silicon in \[\ce{SiO^{4-}4}\] is sp3

(vi) Germanium in [GeCl6]2- is sp3d2

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अध्याय 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १४०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 38 | पृष्ठ १४०

संबंधित प्रश्न

Aluminium trifluoride is insoluble in anhydrous HF but dissolves on the addition of NaF. Aluminium trifluoride precipitates out of the resulting solution when gaseous BF3 is bubbled through. Give reasons.


How would you explain the lower atomic radius of Ga as compared to Al?


Which of the following oxides is acidic in nature?


The exhibition of highest co-ordination number depends on the availability of vacant orbitals in the central atom. Which of the following elements is not likely to act as central atom in \[\ce{MF^{3-}6}\]?


Ionisation enthalpy (∆iH1kJ mol–1) for the elements of Group 13 follows the order.


A compound X, of boron reacts with NH3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with Lithium aluminium hydride. The compounds X and Y are represented by the formulas.


Dry ice is ______.


Which of the following statements are correct. Answer on the basis of Figure.

(i) The two birdged hydrogen atoms and the two boron atoms lie in one plane;

(ii) Out of six B – H bonds two bonds can be described in terms of 3 centre 2-electron bonds.

(iii) Out of six B – H bonds four B – H bonds can be described in terms of 3 centre 2 electron bonds;

(iv) The four-terminal B – H bonds are two centre-two electron regular bonds.


Explain the following:

Electron gain enthalpy of chlorine is more negative as compared to fluorine.


Identify the compounds A, X and Z in the following reactions:

\[\ce{A + 2HCl + 5H2O -> 2NaCl + X}\]


Identify the compounds A, X and Z in the following reactions:

\[\ce{X ->[Δ][370 K] HBO2 ->[Δ][> 370 K] Z}\]


Match the species given in Column I with the properties mentioned in Column II.

Column I Column II
(i) \[\ce{BF^{-}4}\] (a) Oxidation state of central atom is +4
(ii) AICI3 (b) Strong oxidising agent
(iii) SnO (c) Lewis acid
(iv) PbO2 (d) Can be further oxidised
  (e) Tetrahedral shape

Match the species given in Column I with properties given in Column II.

Column I Column II
(i) Diborane (a) Used as a flux for soldering metals
(ii) Galluim (b) Crystalline form of silica
(iii) Borax (c) Banana bonds
(iv) Aluminosilicate (d) Low melting, high boiling, useful for measuring high temperatures
(v) Quartz (e) Used as catalyst in petrochemical industries

Account for the following observations:

Though fluorine is more electronegative than chlorine yet BF3 is a weaker Lewis acid than BCl3 


Three pairs of compounds are given below. Identify that compound in each of the pairs which has group 13 element in more stable oxidation state. Give reason for your choice. State the nature of bonding also.

TlCl3, TlCl


BCl3 exists as monomer whereas AlCl3 is dimerised through halogen bridging. Give reason. Explain the structure of the dimer of AlCl3 also.


Boron compounds behave as Lewis acids because of their ______.


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