Question

Match the species given in Column I with the hybridisation given in Column II.

Column I	Column II
(i) Boron in [B(OH)4]–	(a) sp2
(ii) Aluminium in [Al(H2O)6]3+	(b) sp3
(iii) Boron in B2H6	(c) sp3d2
(iv) Carbon in Buckminsterfullerene
(v) Silicon in \[\ce{SiO^{4-}4}\]
(vi) Germanium in [GeCl6]2–

Answer 1

Column I	Column II
(i) Boron in [B(OH)4]–	(b) sp3
(ii) Aluminium in [Al(H2O)6]3+	(c) sp3d2
(iii) Boron in B2H6	(b) sp3
(iv) Carbon in Buckminsterfullerene	(a) sp2
(v) Silicon in \[\ce{SiO^{4-}4}\]	(b) sp3
(vi) Germanium in [GeCl6]2–	(c) sp3d2

Explanation:

(i) Boron in [B(OH)₄]^– is sp³

(ii) Aluminium in [Al(H₂0)₆]³⁺ is sp³d² hybridized

(iii) Boron in B₂H₆ is sp³

(iv) Carbon in Buckminsterfullerene sp² is hybridised.

(v) Silicon in \[\ce{SiO^{4-}4}\] is sp³

(vi) Germanium in [GeCl₆]^2- is sp³d²