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Match the species given in Column I with the hybridisation given in Column II. Column I Column II (i) Boron in [B(OH)4]– (a) sp2 (ii) Aluminium in [Al(H2O)6]3+ (b) sp3 (iii) Boron in B2H6 (c) sp3d2 - Chemistry

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प्रश्न

Match the species given in Column I with the hybridisation given in Column II.

Column I Column II
(i) Boron in [B(OH)4] (a) sp2
(ii) Aluminium in [Al(H2O)6]3+ (b) sp3
(iii) Boron in B2H6 (c) sp3d2
(iv) Carbon in Buckminsterfullerene  
(v) Silicon in \[\ce{SiO^{4-}4}\]  
(vi) Germanium in [GeCl6]2–  
जोड़ियाँ मिलाइएँ
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उत्तर

Column I Column II
(i) Boron in [B(OH)4] (b) sp3
(ii) Aluminium in [Al(H2O)6]3+ (c) sp3d2
(iii) Boron in B2H6 (b) sp3
(iv) Carbon in Buckminsterfullerene (a) sp2
(v) Silicon in \[\ce{SiO^{4-}4}\] (b) sp3
(vi) Germanium in [GeCl6]2– (c) sp3d2

Explanation:

(i) Boron in [B(OH)4] is sp3

(ii) Aluminium in [Al(H20)6]3+ is sp3d2 hybridized

(iii) Boron in B2H6 is sp3

(iv) Carbon in Buckminsterfullerene sp2 is hybridised.

(v) Silicon in \[\ce{SiO^{4-}4}\] is sp3

(vi) Germanium in [GeCl6]2- is sp3d2

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Group 13 Elements - The Boron Family
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १४०]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
अध्याय 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 38 | पृष्ठ १४०

संबंधित प्रश्न

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If B–Cl bond has a dipole moment, explain why BCl3 molecule has zero dipole moment.


What do you understand by inert pair effect?


The geometry of a complex species can be understood from the knowledge of type of hybridisation of orbitals of central atom. The hybridisation of orbitals of central atom in [Be(OH)4] and the geometry of the complex are respectively.


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In the structure of diborane ______.


Which of the following statements are correct. Answer on the basis of Figure.

(i) The two birdged hydrogen atoms and the two boron atoms lie in one plane;

(ii) Out of six B – H bonds two bonds can be described in terms of 3 centre 2-electron bonds.

(iii) Out of six B – H bonds four B – H bonds can be described in terms of 3 centre 2 electron bonds;

(iv) The four-terminal B – H bonds are two centre-two electron regular bonds.


Explain why the following compounds behave as Lewis acids?

BCl3


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AlCl3


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Column I Column II
(i) Diborane (a) Used as a flux for soldering metals
(ii) Galluim (b) Crystalline form of silica
(iii) Borax (c) Banana bonds
(iv) Aluminosilicate (d) Low melting, high boiling, useful for measuring high temperatures
(v) Quartz (e) Used as catalyst in petrochemical industries

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Ionisation enthalpy


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PbO2 is a stronger oxidising agent than SnO2 


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Which one of the following is the correct statement?


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