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Match the species given in Column I with properties given in Column II. Column I Column II (i) Diborane (a) Used as a flux for soldering metals (ii) Galluim (b) Crystalline form of silica (iii) Bora

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प्रश्न

Match the species given in Column I with properties given in Column II.

Column I Column II
(i) Diborane (a) Used as a flux for soldering metals
(ii) Galluim (b) Crystalline form of silica
(iii) Borax (c) Banana bonds
(iv) Aluminosilicate (d) Low melting, high boiling, useful for measuring high temperatures
(v) Quartz (e) Used as catalyst in petrochemical industries
जोड़ियाँ मिलाइएँ
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उत्तर

Column I Column II
(i) Diborane (a) Used as a flux for soldering metals
(ii) Galluim (b) Crystalline form of silica
(iii) Borax (c) Banana bonds
(iv) Aluminosilicate (d) Low melting, high boiling, useful for measuring high temperatures
(v) Quartz (e) Used as catalyst in petrochemical industries

Explanation:

(i) BH3 is unstable, forms diborane B2H6 by 3 centre –2 electron bonds, shows banana bonds.

(ii) Gallium with low melting point and high boiling point makes it useful to measure high temperatures.

(iii) Borax is used as a flux for soldering metals.

(iv) Aluminosilicate is used as catalyst in petrochemical industries.

(v) Quartz is a crystalline form of silica.

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अध्याय 11: The p-block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १३९]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 11
अध्याय 11 The p-block Elements
Multiple Choice Questions (Type - I) | Q 37 | पृष्ठ १३९

संबंधित प्रश्न

How would you explain the lower atomic radius of Ga as compared to Al?


What do you understand by inert pair effect?


Ionisation enthalpy (∆iH1kJ mol–1) for the elements of Group 13 follows the order.


In the structure of diborane ______.


Explain why the following compounds behave as Lewis acids?

AlCl3


Explain the following:

Boron does not exist as B3+ ion.


Identify the compounds A, X and Z in the following reactions:

\[\ce{X ->[Δ][370 K] HBO2 ->[Δ][> 370 K] Z}\]


Match the species given in Column I with the hybridisation given in Column II.

Column I Column II
(i) Boron in [B(OH)4]– (a) sp2
(ii) Aluminium in [Al(H2O)6]3+ (b) sp3
(iii) Boron in B2H6 (c) sp3d2
(iv) Carbon in Buckminsterfullerene  
(v) Silicon in \[\ce{SiO^{4-}4}\]  
(vi) Germanium in [GeCl6]2–  

Account for the following observations:

Though fluorine is more electronegative than chlorine yet BF3 is a weaker Lewis acid than BCl3 


Account for the following observations:

PbO2 is a stronger oxidising agent than SnO2 


Three pairs of compounds are given below. Identify that compound in each of the pairs which has group 13 element in more stable oxidation state. Give reason for your choice. State the nature of bonding also.

AlCl3 , AlCl


Three pairs of compounds are given below. Identify that compound in each of the pairs which has group 13 element in more stable oxidation state. Give reason for your choice. State the nature of bonding also.

InCl3, InCl


BCl3 exists as monomer whereas AlCl3 is dimerised through halogen bridging. Give reason. Explain the structure of the dimer of AlCl3 also.


Boron compounds behave as Lewis acids because of their ______.


Which one of the following is the correct statement?


Taking stability as the factor, which one of the following represents the correct relationship?


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