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Question
Mahendra and Virat are sitting at a distance of 1m from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them? (G = 6.67 × 10−11 Nm2/kg2)
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Solution
Given:
Distance (r) = 1 m, mass (m1) = 75 kg, mass (m2) = 80 kg, gravitational constant (G) = 6.67 × 10-11 Nm2/kg2
To find:
Gravitational force (F)
F = `("Gm"_1"m"_2)/"r"^2` ...[From formula]
F = `(6.67 xx 10^-11 xx 75 xx 80)/1^2`
∴ F = 4.002 × 10-7 N
The gravitational force between Mahendra and Virat is 4.002 × 10-7 N.
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