Advertisements
Advertisements
Question
A ball is thrown vertically upwards. It goes to a height 20 m and then returns to the ground. Taking acceleration due to gravity g to be 10 ms-2 , find :
the total time of journey of the ball .
Advertisements
Solution
Given, maximum height reached, s = 20 m
Acceleration due to gravity, g = 10 m/s2
Now total time for which the ball remains in air, t = 2u/g.
Or, t = 2 (20)/(10).
Or, t = 4s.
APPEARS IN
RELATED QUESTIONS
Write the answer of the question with reference to laws of gravitation.
State the universal law of gravitation.
Write the formula to find the magnitude of the gravitational force between the earth and an object on the surface of the earth.
Let V and E be the gravitational potential and gravitational field at a distance r from the centre of a uniform spherical shell. Consider the following two statements :
(A) The plot of V against r is discontinuous.
(B) The plot of E against r is discontinuous.
Let V and E represent the gravitational potential and field at a distance r from the centre of a uniform solid sphere. Consider the two statements:
(A) the plot of V against r is discontinuous.
(B) The plot of E against r is discontinuous.
Three uniform spheres each having a mass M and radius a are kept in such a way that each touches the other two. Find the magnitude of the gravitational force on any of the spheres due to the other two.
Define one Newton. How much maximum acceleration can it produce in a mass of 1 kg?
The acceleration produced by a force in an object is directly proportional to the applied _________ And inversely proportional to the _________ Of the object.
All objects in the universe attract each other along the line joining their________.
A ball is thrown up with a speed of 4.9 ms-1.
Calculate the time it takes to reach this height.
Explain the difference between g and G.
