Advertisements
Advertisements
प्रश्न
A ball is thrown vertically upwards. It goes to a height 20 m and then returns to the ground. Taking acceleration due to gravity g to be 10 ms-2 , find :
the total time of journey of the ball .
Advertisements
उत्तर
Given, maximum height reached, s = 20 m
Acceleration due to gravity, g = 10 m/s2
Now total time for which the ball remains in air, t = 2u/g.
Or, t = 2 (20)/(10).
Or, t = 4s.
APPEARS IN
संबंधित प्रश्न
Write the answer of the question with reference to laws of gravitation.
State the universal law of gravitation.
Can you think of two particles which do not exert gravitational force on each other?
A person sitting in a chair in a satellite feels weightless because
The mass of moon is about 0.012 times that of earth and its diameter is about 0.25 times that of earth. The value of G on the moon will be:
Who stated the law of gravitation?
At what height above the earth's surface would the value of acceleration due to gravity be half of what it is on the surface? Take the radius of earth to be R.
Solve the following problem.
Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 1024 kg, R = 6400 km).
The gravitational force between two bodies is directly proportional to the product of the masses of those bodies and is ______ of the distance between them.
The gravitational force between a hollow spherical shell (of radius R and uniform density) and a point mass is F. Show the nature of F vs r graph where r is the distance of the point from the centre of the hollow spherical shell of uniform density.
The gravitational force between a hollow spherical shell (of radius R and uniform density) and a point mass is F. Show the nature of F vs r graph where r is the distance of the point from the centre of the hollow spherical shell of uniform density.
