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Limx→π4sec2x-2tanx-1 is equal to ______.

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Question

`lim_(x -> pi/4) (sec^2x - 2)/(tan x - 1)` is equal to ______.

Options

  • 3

  • 1

  • 0

  • 2

MCQ
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Solution

`lim_(x -> pi/4) (sec^2x - 2)/(tan x - 1)` is equal to 2.

Explanation:

Given, `lim_(x -> pi/4) (sec^2 x - 2)/(tan x - 1)`

= `lim_(x -> pi/4) (1 + tan^2 x - 2)/(tan x - 1)`

= `lim_(x -> pi/4) (tan^2x - 1)/(tanx - 1)`

= `lim_(x -> pi/4) ((tan x + 1)(tan x - 1))/((tan x - 1))`

= `lim_(x -> pi/4) (tan x + 1)`

= `tan  pi/4 + 1`

= 1 + 1

= 2

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Chapter 13: Limits and Derivatives - Exercise [Page 243]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 13 Limits and Derivatives
Exercise | Q 61 | Page 243

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