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Limx→0sinxx+1-1-x is ______.

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Question

`lim_(x -> 0) sinx/(sqrt(x + 1) - sqrt(1 - x)` is ______.

Options

  • 2

  • 0

  • 1

  • –1

MCQ
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Solution

`lim_(x -> 0) sinx/(sqrt(x + 1) - sqrt(1 - x)` is 1.

Explanation:

Given `lim_(x -> 0) sinx/(sqrt(x + 1) - sqrt(1 - x))`

= `lim_(x -> 0) (sinx [sqrt(x + 1) + sqrt(1 - x)])/((sqrt(x + 1) - sqrt(1 - x))(sqrt(x + 1) + sqrt(1  - x))`

= `lim_(x -> 0) (sin x[sqrt(x + 1) + sqrt(1 - x)])/(x + 1 - 1 + x)`

= `lim_(x -> 0) (sin x[sqrt(x + 1) + sqrt(1 - x)])/(2x)`

= `1/2 * lim_(x -> 0) sinx/x [sqrt(x + 1) + sqrt(1 - x)]`

Taking limit, we get

= `1/2 xx 1 xx [sqrt(0 + 1) + sqrt(1 - 0)]`

= `1/2 xx 1 xx 2`

= 1

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Chapter 13: Limits and Derivatives - Exercise [Page 243]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 13 Limits and Derivatives
Exercise | Q 60 | Page 243

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