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Limx→0tan2x-x3x-sinx is equal to ______.

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Question

`lim_(x -> 0) (tan 2x - x)/(3x - sin x)` is equal to ______.

Options

  • 2

  • `1/2`

  • `-1/2`

  • `1/4`

MCQ
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Solution

`lim_(x -> 0) (tan 2x - x)/(3x - sin x)` is equal to `1/2`.

Explanation:

Given `lim_(x -> 0) (tan 2x - x)/(3x - sin x)`

= `lim_(x -> 0) (x[tan2x/x - 1])/(x[3 - sin x/x])`

`lim_((x -> 0),(because  2x -> 0)) ((tan 2x)/(2x) xx 2 - 1)/(3 - sinx/x)`

= `(1.2 - 1)/(3 - 1)`

= `(2 - 1)/2`

= `1/2`

∴ 2x → 0

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Chapter 13: Limits and Derivatives - Exercise [Page 244]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 13 Limits and Derivatives
Exercise | Q 66 | Page 244

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