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Evaluate the following : limx→0[secx2-1x4]

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Question

Evaluate the following :

`lim_(x -> 0)[(secx^2 - 1)/x^4]`

Sum
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Solution

`lim_(x -> 0)(secx^2 - 1)/x^4`

Put x2 = y

As x → 0, x2 → 0

∴ y → 0

∴ Required limit

= `lim_(y -> 0) (sec y - 1)/(y^2)`

= `lim_(y -> 0) (sec y - 1)/(y^2) xx (sec y + 1)/(sec y + 1)`

= `lim_(y -> 0) (sec^2 y - 1)/(y^2(sec y + 1))`

= `lim_(y -> 0) (tan^2 y)/(y^2(sec y + 1))`

= `lim_(y -> 0) (tan^2 y)/(y^2) xx 1/(sec y + 1)`

= `lim_(y -> 0) ((tan^2 y)/y^2) xx lim_(y -> 0) 1/(sec y + 1)`

= `(1)^2 xx 1/(1 + 1)`

= `1/2`

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Chapter 7: Limits - Miscellaneous Exercise 7.2 [Page 159]

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