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Evaluate the following limit. limx→π2tan2xx-π2

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Question

Evaluate the following limit.

`lim_(x -> (pi)/2) (tan 2x)/(x - pi/2)`

Sum
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Solution

Substituting x = `π/2 + h` in `lim_(x → π/2) (tan2x)/(x - π/2)`,

= `lim_(h → 0) (tan 2(π/2 + h))/h`

= `lim_(h → 0) (tan(π + 2h))/h`

= `lim_(h → 0) (tan 2h)/h`

= `lim_(h → 0) (sin 2h)/2h . 2/(cos 2h)`

= `lim_(h → 0) 2/(cos 2h)`        ....`(∵ lim_(h → 0) (sin2h)/(2h) = 1)`

= `2/cos0`

= `2/1`

= 2

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Chapter 12: Limits and Derivatives - EXERCISE 12.1 [Page 238]

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NCERT Mathematics [English] Class 11
Chapter 12 Limits and Derivatives
EXERCISE 12.1 | Q 22. | Page 238

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