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Evaluate the following limit. limx→π2tan2xx-π2 - Mathematics

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प्रश्न

Evaluate the following limit.

`lim_(x -> (pi)/2) (tan 2x)/(x - pi/2)`

योग
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उत्तर

Substituting x = `π/2 + h` in `lim_(x → π/2) (tan2x)/(x - π/2)`,

= `lim_(h → 0) (tan 2(π/2 + h))/h`

= `lim_(h → 0) (tan(π + 2h))/h`

= `lim_(h → 0) (tan 2h)/h`

= `lim_(h → 0) (sin 2h)/2h . 2/(cos 2h)`

= `lim_(h → 0) 2/(cos 2h)`        ....`(∵ lim_(h → 0) (sin2h)/(2h) = 1)`

= `2/cos0`

= `2/1`

= 2

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अध्याय 13: Limits and Derivatives - Exercise 13.1 [पृष्ठ ३०२]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 13 Limits and Derivatives
Exercise 13.1 | Q 22 | पृष्ठ ३०२

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