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Evaluate the following : limx→a[sinx-sinax-a]

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Question

Evaluate the following :

`lim_(x -> "a") [(sinx - sin"a")/(x - "a")]`

Sum
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Solution

`lim_(x -> "a") (sinx - sin"a")/(x - "a")`

Put x = a + h,

∴ x – a = h

As x → a, h → 0

∴ `lim_(x -> "a") (sinx - sin"a")/(x - "a")`

= `lim_("h" -> 0) (sin "a" + "h" - sin"a")/"h"`

= `lim_("h" -> 0) (2cos (("a" + "h" + "a")/2) sin(("a" + "h" - "a")/2))/"h"`

= `lim_("h" -> 0) (2cos("a" + "h"/2) sin  "h"/2)/"h"`

= `lim_("h" -> 0) cos ("a" + "h"/2) * lim_("h" -> 0) (sin("h"/2))/(("h"/2))`

= `cos ("a" + 0)(1)  ...[because "h" -> 0, "h"/2 -> 0  "and" lim_(theta -> 0) sintheta/theta = 1]`

= cos a

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Chapter 7: Limits - Miscellaneous Exercise 7.2 [Page 159]

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