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Evaluate the following : limx→0[a3x-a2x-ax+1x⋅tanx]

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Question

Evaluate the following :

`lim_(x -> 0) [("a"^(3x) - "a"^(2x) - "a"^x + 1)/(x*tanx)]`

Sum
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Solution

`lim_(x -> 0) [("a"^(3x) - "a"^(2x) - "a"^x + 1)/(x*tanx)]`

= `lim_(x -> 0) ("a"^(2x) * "a"^x - "a"^(2x) - "a"^x + 1)/(xtanx)`

= `lim_(x -> 0) ("a"^(2x)("a"^x - 1) - ("a"^x - 1))/(xtanx)`

= `lim_(x -> 0) (("a"^x - 1)("a"^(2x) - 1))/(xtanx)`

= `lim_(x -> 0)((("a"^x - 1)/x)(("a"^(2x) - 1)/x))/((tanx/x)`  ...[∵ x → 0, ∴ x ≠ 0]

= `((lim_(x -> 0) ("a"^x - 1)/x) xx (lim_(x -> 0) (("a"^2)^x - 1)/x))/((lim_(x -> 0) tanx/x))`

= `((log "a")(log "a"^2))/1   ...[because lim_(x -> 0) ("a"^x - 1)/x = log "a"]`

= (log a)(2 log a)

= 2(log a)2

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Chapter 7: Limits - Miscellaneous Exercise 7.2 [Page 159]

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