English

Select the correct answer from the given alternatives. limx→0(3+5x3-4x)1x = - Mathematics and Statistics

Advertisements
Advertisements

Question

Select the correct answer from the given alternatives.

`lim_(x -> 0) ((3 + 5x)/(3 - 4x))^(1/x)` =

Options

  • e3 

  • e6 

  • e9 

  • e-3  

MCQ
Advertisements

Solution

`lim_(x -> 0) ((3 + 5x)/(3 - 4x))^(1/x)` =  e3 

Explanation:

`lim_(x -> 0) ((3 + 5x)/(3 - 4x))^(1/x)`

= `lim_(x -> 0)((1 + (5x)/3)/(1 - (4x)/3))^(1/x)`                  ...[Divide numberator and denominator by 3]

= `(lim_(x -> 0)[(1 + (5x)/3)^(3/(5x))]^(5/3))/(lim_(x -> 0)[(1 - (4x)/3)^((-3)/(4x))]^((-4)/3))`

= `e^(5/3)/e^((-4)/3)`

= e3

shaalaa.com
Limits of Exponential and Logarithmic Functions
  Is there an error in this question or solution?
Chapter 7: Limits - Miscellaneous Exercise 7.1 [Page 158]

APPEARS IN

RELATED QUESTIONS

Evaluate the following: `lim_(x -> 0)[(9^x - 5^x)/(4^x - 1)]`


Evaluate the following: `lim_(x -> 0)[(5^x + 3^x - 2^x - 1)/x]`


Evaluate the following: `lim_(x -> 0)[(log(2 + x) - log( 2 - x))/x]`


Evaluate the following: `lim_(x -> 0) [(3 + x)/(3 - x)]^(1/x)`


Evaluate the following Limits: `lim_(x -> 0)[(5^x - 1)/x]`


Evaluate the following Limits: `lim_(x -> 0)[("a"^x + "b"^x + "c"^x - 3)/x]`


Evaluate the following Limits: `lim_(x -> 0) [("a"^(4x) - 1)/("b"^(2x) - 1)]`


Evaluate the following Limits: `lim_(x -> 0)[(log(4 - x) - log(4 + x))/x]`


Evaluate the following limit : 

`lim_(x -> 0) [(5^x + 3^x - 2^x - 1)/x]`


Evaluate the following limit : 

`lim_(x -> 0)[(5x + 3)/(3 - 2x)]^(2/x)`


Evaluate the following limit : 

`lim_(x -> 0) [(log(3 - x) - log(3 + x))/x]`


Evaluate the following limit : 

`lim_(x -> 0)[(2^x - 1)^3/((3^x - 1)*sinx*log(1 + x))]`


Select the correct answer from the given alternatives.

`lim_(x→0)[(3^(sinx) - 1)^3/((3^x - 1).tan x.log(1 + x))]` =


Evaluate the following :

`lim_(x -> 0)[("e"^x + "e"^-x - 2)/(x*tanx)]`


Evaluate the following :

`lim_(x -> 1) [("ab"^x - "a"^x"b")/(x^2 - 1)]`


Evaluate the following : 

`lim_(x -> 0) [((5^x - 1)^2)/((2^x - 1)log(1 + x))]`


lf the function f(x) satisfies `lim_{x→1}(2f(x) - 5)/(2(x^2 - 1)) = e`, then `lim_{x→1}f(x)` is ______ 


`lim_(x -> 0) (log(1 + (5x)/2))/x` is equal to ______.


The value of `lim_{x→0} (1 + sinx - cosx + log_e(1 - x))/x^3` is ______


The value of `lim_{x→2} (e^{3x - 6} - 1)/(sin(2 - x))` is ______ 


Evaluate the following Limit.

`lim_(x->1)[(x^3-1)/(x^2+5x-6)]`


Evaluate the following :

`lim_(x -> 0) [((25)^x - 2(5)^x + 1)/x^2]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/x^2]`


Evaluate the following limit :

`lim(x>2)[(z^2 -5z+6)/(z^2-4)]`


Evaluate the following limit :

`lim_(x->0)[(sqrt(6+x+x^2)-sqrt6)/x]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/x^2]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/x^2]`


Evaluate the following :

`lim_(x->0)[((25)^x -2 (5)^x +1)/(x^2)]`


Evaluate the following:

`lim_(x->0)[((25)^x - 2(5)^x + 1)/(x^2)]`


Evaluate the limit: 

`lim_(z->2)[(z^2-5x+6)/(z^2-4)]`


Evaluate the following:

`lim_(x->0)[((25)^x -2(5)^x +1)/(x^2)]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×