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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Select the correct answer from the given alternatives. limx→0(3+5x3-4x)1x =

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प्रश्न

Select the correct answer from the given alternatives.

`lim_(x -> 0) ((3 + 5x)/(3 - 4x))^(1/x)` =

पर्याय

  • e3 

  • e6 

  • e9 

  • e-3  

MCQ
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उत्तर

`lim_(x -> 0) ((3 + 5x)/(3 - 4x))^(1/x)` =  e3 

Explanation:

`lim_(x -> 0) ((3 + 5x)/(3 - 4x))^(1/x)`

= `lim_(x -> 0)((1 + (5x)/3)/(1 - (4x)/3))^(1/x)`                  ...[Divide numberator and denominator by 3]

= `(lim_(x -> 0)[(1 + (5x)/3)^(3/(5x))]^(5/3))/(lim_(x -> 0)[(1 - (4x)/3)^((-3)/(4x))]^((-4)/3))`

= `e^(5/3)/e^((-4)/3)`

= e3

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Limits - Miscellaneous Exercise 7.1 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
पाठ 7 Limits
Miscellaneous Exercise 7.1 | Q I. (9) | पृष्ठ १५८

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