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Evaluate the following : limx→0[(5x-1)2(2x-1)log(1+x)] - Mathematics and Statistics

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प्रश्न

Evaluate the following : 

`lim_(x -> 0) [((5^x - 1)^2)/((2^x - 1)log(1 + x))]`

बेरीज
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उत्तर

`lim_(x -> 0) ((5^x - 1)^2)/((2^x - 1)log(1 + x))`

= `lim_(x -> 0)((5^x - 1)^2/x^2)/(((2^x - 1)*log(1 + x))/x^2)   ...[("Divide numerator and"),("denominator by"  x^2.),(because x -> 0","  x ≠ 0),(therefore x^2 ≠ 0)]`

= `(lim_(x -> 0) ((5^x - 1)/x)^2)/(lim_(x -> 0) ((2^x - 1)/x)*(log(1 + x))/x`

= `(lim_(x -> 0) (5^x - 1)/x)^2/(lim_(x -> 0) ((2^x - 1)/x)*lim_(x -> 0) (log(1 + x))/x)`

= `(log5)^2/(log2 xx 1)  ....[lim_(x -> 0) ("a"^x - 1)/x = log"a"]`

= `(log5)^2/log2`

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पाठ 7: Limits - Miscellaneous Exercise 7.2 [पृष्ठ १५९]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 7 Limits
Miscellaneous Exercise 7.2 | Q II. (14) | पृष्ठ १५९

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