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Evaluate: limx→1x7-2x5+1x3-3x2+2 - Mathematics

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Question

Evaluate: `lim_(x -> 1) (x^7 - 2x^5 + 1)/(x^3 - 3x^2 + 2)`

Sum
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Solution

Given that `lim_(x -> 1) (x^7 - 2x^5 + 1)/(x^3 - 3x^2 + 2)`   .....`[0/0  "form"]`

= `lim_(x -> 1) (x^7 - x^5 - x^5 + 1)/(x^3 - x^2 - 2x^2 + 2)`

= `lim_(x -> 1) (x^5(x^2 - 1) - 1(x^5 - 1))/(x^2(x - 1) - 2(x^2 - 1))`

Dividing the numerator and denominator by (x – 1) we get

= `lim_(x -> 1) (x^5 ((x^2 - 1)/(x - 1)) - 1((x^5 - 1)/(x - 1)))/(x^2((x - 1)/(x - 1)) - 2((x^2 - 1)/(x - 1))`

= `(lim_(x -> 1) x^5 (x + 1) - lim_(x -> 1) ((x^5 - (1)^5)/(x - 1)))/(lim_(x -> 1) x^2 - 2 lim_(x -> 1) (x + 1))`

= `(1(2) - 5 * (1)^(5 - 1))/(1 - 2(2))`

= `(2 - 5)/(1 - 4)`

= `(-3)/(--3)`

= 1

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Chapter 13: Limits and Derivatives - Exercise [Page 240]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 13 Limits and Derivatives
Exercise | Q 10 | Page 240

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