English
Karnataka Board PUCPUC Science Class 11

Lifetimes of the molecules in the excited states are often measured by using pulsed radiation source of duration nearly in the nano second range.

Advertisements
Advertisements

Question

Lifetimes of the molecules in the excited states are often measured by using pulsed radiation source of duration nearly in the nanosecond range. If the radiation source has a duration of 2 ns and the number of photons emitted during the pulse source is 2.5 × 1015, calculate the energy of the source.

Numerical
Advertisements

Solution

Frequency of radiation (ν),

`"v" = 1/(2.0 xx 10^(9))`

`"v" = 5.0 xx 10^8 " s"^(-1)`

Energy (E) of source = Nhν

Where,

N = number of photons emitted

h = Planck’s constant

ν = frequency of radiation

Substituting the values in the given expression of (E):

E = (2.5 × 1015) (6.626 × 10–34 Js) (5.0 × 108 s–1)

E = 8.282 × 10–10 J

Hence, the energy of the source (E) is 8.282 × 10–10 J.

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Structure of Atom - EXERCISES [Page 72]

APPEARS IN

NCERT Chemistry Part 1 and 2 [English] Class 11
Chapter 2 Structure of Atom
EXERCISES | Q 2.49 | Page 72

RELATED QUESTIONS

Using Bohr's postulates of the atomic model, derive the expression for radius of nth electron orbit. Hence obtain the expression for Bohr's radius.


The energy associated with the first orbit in the hydrogen atom is - 2.18 × 10-18 J atom-1. What is the energy associated with the fifth orbit?


How many electrons in an atom may have the following quantum numbers?

n = 4, `m_s =  -1/2`


The longest wavelength doublet absorption transition is observed at 589 and 589.6 nm. Calculate the frequency of each transition and energy difference between two excited states.


In Bohr’s model of the hydrogen atom, the radius of the first orbit of an electron is r0 . Then, the radius of the third orbit is:

a) `r_0/9`

b) `r_0`

c) `3r_0`

d) `9r_0`


Using Bohr’s postulates, obtain the expression for the total energy of the electron in the stationary states of the hydrogen atom. Hence draw the energy level diagram showing how the line spectra corresponding to Balmer series occur due to transition between energy levels.


The numerical value of ionization energy in eV equals the ionization potential in volts. Does the equality hold if these quantities are measured in some other units?


Draw energy level diagram for a hydrogen atom, showing the first four energy levels corresponding to n=1, 2, 3 and 4. Show transitions responsible for:
(i) Absorption spectrum of Lyman series.
(ii) The emission spectrum of the Balmer series.


Mention demerits of Bohr’s Atomic model.


According to Bohr’s theory, the angular momentum of an electron in 5th orbit is ______.


According to the Bohr theory of H-atom, the speed of the electron, its energy and the radius of its orbit varies with the principal quantum number n, respectively, as:


The energy of an electron in hth orbit of hydrogen atom is –13.6/n2ev energy required to excite the electron from the first orbit to the third orbit is


For the ground state, the electron in the H-atom has an angular momentum = h, according to the simple Bohr model. Angular momentum is a vector and hence there will be infinitely many orbits with the vector pointing in all possible directions. In actuality, this is not true ______.


An ionised H-molecule consists of an electron and two protons. The protons are separated by a small distance of the order of angstrom. In the ground state ______.

  1. the electron would not move in circular orbits.
  2. the energy would be (2)4 times that of a H-atom.
  3. the electrons, orbit would go around the protons.
  4. the molecule will soon decay in a proton and a H-atom.

Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength λ. If R is the Rydberg constant then the principal quantum number n of the excited state is ______.


What is meant by ionisation energy?


Calculate the radius of the second orbit of He+.


For the reaction \[\ce{2NO2 (g) ⇌ N2O4(g)}\], when ΔS = −176.0 JK−1 and ΔH = −57.8 kj mol−1, the magnitude of ΔG at 298 K for the reaction is ______ kJ mol−1. (Nearest integer)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×