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Karnataka Board PUCPUC Science Class 11

Calculate the Magnetic Dipole Moment Corresponding to the Motion of the Electron in the Ground State of a Hydrogen Atom.

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Question

Calculate the magnetic dipole moment corresponding to the motion of the electron in the ground state of a hydrogen atom.

Sum
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Solution

Mass of the electron, m = 9.1×10-31kg

Radius of the ground state, r = 0.53×10-10m

Let  f be the frequency of revolution of the electron moving in ground state and A be the area of orbit.

Dipole moment of the electron (μ) is given by

μ = niA = qfA

`= e xx (me^4)/(4∈_0^2h^3n^3)xx(pi^2n^2)`

`= (me^5xx (pir^2n^2))/(4∈_0^2h^3n^3)`

Here,

h = Planck's constant

=  Charge on the electron

`epsilon_0` = Permittivity of free space

n = Principal quantum number

`therefore  mu = ((9.1xx10^-13)(1.6xx10^-19)^5xxpi xx(0.53xx10^-10)^2)/(4 xx (8.85xx10^-12)^2xx(6.64xx10^-34)^3xx(1)^3`
= 0.000917 × 10-20
= 9.176 × 10-24 A-m25

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Chapter 43: Bohr’s Model and Physics of Atom - Exercises [Page 385]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 43 Bohr’s Model and Physics of Atom
Exercises | Q 25 | Page 385

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