Question

The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths, λ₁/λ₂, of the photons emitted in this process is ______. 

Options

• 20/7

• 27/5

• 7/5

• 9/7

Answer 1

The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths, λ₁/λ₂, of the photons emitted in this process is 20/7.

Explanation:

`1/lambda_1="R"(1/3^2-1/4^2)=(7"R")/(16xx9)`

And = `1/lambda_2="R"(1/2^2-1/3^2)=(5"R")/36` 

Now `lambda_1/lambda_2= ((5"R"//36))/(7"R"//(16xx9)) = 20/7`