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Question
In the circuit shown in the figure, the BJT has a current gain (β) of 50. For an emitter-base voltage VEB = 600 mV, calculate the emitter-collector voltage VEC (in volts).
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Solution
β = 50
VEB = 600 × 10−3 V
RB = 60 k Ω
RC = 500 k Ω
VB = VE – VEB
= 3 – 0.6
= 2.4 V
IB = `"V"_"B"/"R"_"B"`
= `2.4/(60 xx 10^9)`
= 0.04 × 10−3 A
IB = 40 µA
IC = β IB
= 50 × 40 × 10−6
IC = 2 mA
VC = IC RC = 500 IC
= 500 × 2 × 10−3
VEC = VE – VC
= 3 – 1
= 2 V
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