Question

In the circuit shown in the figure, the BJT has a current gain (β) of 50. For an emitter-base voltage V_EB = 600 mV, calculate the emitter-collector voltage V_EC (in volts).

Answer 1

β = 50

V_EB = 600 × 10⁻³ V

R_B = 60 k Ω

R_C = 500 k Ω

V_B = V_E – V_EB

= 3 – 0.6

= 2.4 V

I_B = `"V"_"B"/"R"_"B"`

= `2.4/(60 xx 10^9)`

= 0.04 × 10⁻³ A

I_B = 40 µA

I_C = β I_B

= 50 × 40 × 10⁻⁶

I_C = 2 mA

V_C = I_C R_C = 500 I_C

= 500 × 2 × 10⁻³

V_EC = V_E – V_C

= 3 – 1

= 2 V