Advertisements
Advertisements
प्रश्न
In the circuit shown in the figure, the BJT has a current gain (β) of 50. For an emitter-base voltage VEB = 600 mV, calculate the emitter-collector voltage VEC (in volts).
Advertisements
उत्तर
β = 50
VEB = 600 × 10−3 V
RB = 60 k Ω
RC = 500 k Ω
VB = VE – VEB
= 3 – 0.6
= 2.4 V
IB = `"V"_"B"/"R"_"B"`
= `2.4/(60 xx 10^9)`
= 0.04 × 10−3 A
IB = 40 µA
IC = β IB
= 50 × 40 × 10−6
IC = 2 mA
VC = IC RC = 500 IC
= 500 × 2 × 10−3
VEC = VE – VC
= 3 – 1
= 2 V
APPEARS IN
संबंधित प्रश्न
Why are the emitter, the base, and the collector of a BJT doped differently?
In a common-base connection, a certain transistor has an emitter current of 10mA and a collector current of 9.8 mA. Calculate the value of the base current.
Derive the relation between α and β.
Which method of biasing is used for operating a transistor as an amplifier?
In a common base configuration, the transistor has an emitter current of 10 mA and a collector current of 9.8 mA. The value of base current is ______
Draw the circuit symbol of the PNP transistor.
In the symbol for a transistor, the arrow head points in the direction of the ____________.
In a transistor in CE configuration, the ratio of power gain to voltage gain is ____________.
A pnp transistor is used in common-emitter mode. If a change of 40 µA in base current brings a change of 2 µA in collector current with 0.04 V in base-emitter voltage, then the input resistance is ____________.
A conducting wire has length 'L1' and diameter 'd1'. After stretching the same wire length becomes 'L2' and diameter 'd2' The ratio of resistances before and after stretching is ______.
