English

In the Given Figure, What is the Value of X? - Mathematics

Advertisements
Advertisements

Question

In the given figure, what is the value of x?

Options

  • 35

  • 45

  • 50

  • 60

MCQ
Advertisements

Solution

In the given figure, we need to find the value of x.

Here, DBA is a straight line, so using the property, “angles forming a linear pair are supplementary”, we get,

∠CBA + ∠CBD = 180°

          7y + 5y = 180°

                12y = 180°

                   `y = (180°)/12`

                    y = 15°

Now, applying the value of y in ∠CBA and ∠BCA

∠BCA = 3y

          = 3(15°)

          = 45°

Also,

∠CBA = 5y

          = 5(15°)

          = 75°

Further, applying angle sum property of the triangle

In ΔABC

∠A + ∠B +∠C = 180°

   x + 75° + 45° = 180°

         x + 120°= 180°

                  x = 180° - 120°

                  x = 60°

Thus,  x = 60°

shaalaa.com
  Is there an error in this question or solution?
Chapter 11: Triangle and its Angles - Exercise 11.4 [Page 27]

APPEARS IN

RD Sharma Mathematics [English] Class 9
Chapter 11 Triangle and its Angles
Exercise 11.4 | Q 20 | Page 27

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

In an isosceles triangle ABC, with AB = AC, the bisectors of ∠B and ∠C intersect each other at O. Join A to O. Show that:

  1. OB = OC
  2. AO bisects ∠A

In a ΔABC, if ∠A=l20° and AB = AC. Find ∠B and ∠C. 

 


AB is a line seg P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B (See Fig. 10.26). Show that the line PQ is perpendicular bisector of AB. 

 


Two lines AB and CD intersect at O such that BC is equal and parallel to AD. Prove that the lines AB and CD bisect at O.


In an isosceles triangle, if the vertex angle is twice the sum of the base angles, calculate the angles of the triangle. 


PQR is a triangle in which PQ = PR and S is any point on the side PQ. Through S, a line is drawn parallel to QR and intersecting PR at T. Prove that PS = PT.  

 


P is a point on the bisector of an angle ∠ABC. If the line through P parallel to AB meets BC at Q, prove that triangle BPQ is isosceles.  

 


Angles A, B, C of a triangle ABC are equal to each other. Prove that ΔABC is equilateral. 


ABC is a triangle and D is the mid-point of BC. The perpendiculars from D to AB and AC are equal. Prove that the triangle is isosceles. 


ABC is a triangle in which BE and CF are, respectively, the perpendiculars to the sides AC and AB. If BE = CF, prove that ΔABC is isosceles  


In ΔABC, side AB is produced to D so that BD = BC. If ∠B = 60° and ∠A = 70°, prove that: (i) AD > CD (ii) AD > AC 


Prove that the perimeter of a triangle is greater than the sum of its altitudes. 


Fill in the blank to make the following statement true. 

In a right triangle the hypotenuse is the .... side. 


In the given figure, AB and CD are parallel lines and transversal EF intersects them at Pand Q respectively. If ∠APR = 25°, ∠RQC = 30° and ∠CQF = 65°, then


In a ΔABC, ∠A = 50° and BC is produced to a point D. If the bisectors of ∠ABC and ∠ACDmeet at E, then ∠E =


The angles of a right angled triangle are


D is a point on the side BC of a ∆ABC such that AD bisects ∠BAC. Then ______.


M is a point on side BC of a triangle ABC such that AM is the bisector of ∠BAC. Is it true to say that perimeter of the triangle is greater than 2 AM? Give reason for your answer.


ABC is an isosceles triangle with AB = AC and D is a point on BC such that AD ⊥ BC (Figure). To prove that ∠BAD = ∠CAD, a student proceeded as follows:


In ∆ABD and ∆ACD,

AB = AC (Given)

∠B = ∠C (Because AB = AC)

and ∠ADB = ∠ADC

Therefore, ∆ABD ≅ ∆ACD (AAS)

So, ∠BAD = ∠CAD (CPCT)

What is the defect in the above arguments?

[Hint: Recall how ∠B = ∠C is proved when AB = AC].


Show that in a quadrilateral ABCD, AB + BC + CD + DA < 2(BD + AC)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×