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ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see the given figure). Show that i. ΔABE ≅ ΔACF ii. AB = AC, i.e., ABC is an isosceles triangle. - Mathematics

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Question

ABC is a triangle in which altitudes BE and CF to sides AC and AB are equal (see the given figure). Show that

  1. ΔABE ≅ ΔACF
  2. AB = AC, i.e., ABC is an isosceles triangle.

Sum
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Solution

i. In △ABE and △ACF, we have

∠AEB = ∠AFC      ...[Each = 90° as BE ⊥ AC and CF ⊥ AB]

∠A = ∠A        ...[Common]

BE = CF         ...[Given]

∴ △ABE ≌ △ACF      ...[By AAS congruence rule]

ii. Since, △ABE ≌ △ACF

∴ AB = AC       ...[By Corresponding parts of congruent triangles]

⇒ ABC is an isosceles triangle.

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Chapter 7: Triangles - EXERCISE 7.2 [Page 98]

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NCERT Mathematics [English] Class 9
Chapter 7 Triangles
EXERCISE 7.2 | Q 4. | Page 98

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