Question

 In Given Figure, find tan P – cot R.

Answer 1

Applying Pythagoras theorem for ΔPQR, we obtain

PR² = PQ² + QR²

(13 cm)² = (12 cm)² + QR²

169 cm² = 144 cm² + QR²

25 cm² = QR²

QR = 5 cm

tan P = `("Side opposite to ∠P")/("Side adjacent to ∠P") = ("QR")/("PQ")`

= `5/12`

cot R = `("Side opposite to ∠R")/("Side adjacent to ∠R") = ("QR")/("PQ")`

= `5/12`

tan P - cot R = `5/12 - 5/12 = 0`