Advertisements
Advertisements
Question
If θ is an acute angle of a right angled triangle, then which of the following equation is not true?
Options
sin θ cot θ = cos θ
cos θ tan θ = sin θ
cosec2 θ – cot2 θ = 1
tan2 θ – sec2 θ = 1
Advertisements
Solution
tan2 θ – sec2 θ = 1
Explanation:
tan2 θ – sec2 θ = 1 is not true
∵ sec2 θ = 1 + tan2 θ
or sec2 θ – tan2 θ = 1
APPEARS IN
RELATED QUESTIONS
If cot θ = `7/8`, evaluate cot2 θ.
In ΔABC, right angled at B. If tan A = `1/sqrt3` , find the value of
- sin A cos C + cos A sin C
- cos A cos C − sin A sin C
Prove that `(sin "A" - 2sin^3 "A")/(2cos^3 "A" - cos "A") = tan "A"`
If tan θ = `a/b` prove that `(a sin theta - b cos theta)/(a sin theta + b cos theta) = (a^2 - b^2)/(a^2 + b^2)`
If `sin theta = a/b` find sec θ + tan θ in terms of a and b.
Evaluate the following
sin2 30° + sin2 45° + sin2 60° + sin2 90°
If cosec θ - cot θ = `1/3`, the value of (cosec θ + cot θ) is ______.
The value of cos 0°. cos 1°. cos 2°. cos 3°… cos 89° cos 90° is ______.
In a right triangle PQR, right angled at Q. If tan P = `sqrt(3)`, then evaluate 2 sin P cos P.

In ΔBC, right angled at C, if tan A = `8/7`, then the value of cot B is ______.

