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In Given Figure, find tan P – cot R. - Mathematics

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प्रश्न

 In Given Figure, find tan P – cot R.

बेरीज
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उत्तर

Applying Pythagoras theorem for ΔPQR, we obtain

PR2 = PQ2 + QR2

(13 cm)2 = (12 cm)2 + QR2

169 cm2 = 144 cm2 + QR2

25 cm2 = QR2

QR = 5 cm

tan P = `("Side opposite to ∠P")/("Side adjacent to ∠P") = ("QR")/("PQ")`

= `5/12`

cot R = `("Side opposite to ∠R")/("Side adjacent to ∠R") = ("QR")/("PQ")`

= `5/12`

tan P - cot R = `5/12 - 5/12 = 0`

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पाठ 8: Introduction to Trigonometry - Exercise 8.1 [पृष्ठ १८१]

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एनसीईआरटी Mathematics [English] Class 10
पाठ 8 Introduction to Trigonometry
Exercise 8.1 | Q 2 | पृष्ठ १८१

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