मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Prove that sec θ + tan θ = cos θ/(1 - sin θ). Proof: L.H.S. = sec θ + tan θ = 1/square + square/square = square/square  ......(∵ sec θ = 1/square, tan θ = square/square)

Advertisements
Advertisements

प्रश्न

Prove that sec θ + tan θ = `cos θ/(1 - sin θ)`.

Proof: L.H.S. = sec θ + tan θ

= `1/square + square/square`

= `square/square`  ......`(∵ sec θ = 1/square, tan θ = square/square)`

= `((1 + sin θ) square)/(cos θ  square)`  ......[Multiplying `square` with the numerator and denominator]

= `(1^2 - square)/(cos θ  square)`

= `square/(cos θ  square)`

= `cos θ/(1 - sin θ)` = R.H.S.

∴ L.H.S. = R.H.S.

∴ sec θ + tan θ = `cos θ/(1 - sin θ)`

रिकाम्या जागा भरा
बेरीज
Advertisements

उत्तर

Proof: L.H.S. = sec θ + tan θ

= `1/bb(cos  θ) + bb(sin  θ)/bb(cos  θ)`    ........`[∵ sec θ = 1/bb(cos  θ), tan θ = bb(sin  θ)/bb(cos  θ)]`

= `bb(1 + sintheta)/bbcostheta` = `((1 + sin θ) bb(1 - sin  θ))/(cos θ  bb(1 - sin  θ)`  ......[Multiplying `bb(1 - sin  θ)` with the numerator and denominator]

= `(1^2 - bb(sin^2 θ))/(cos θ  bb(1 - sin  θ)`

= `bb (cos^2 θ)/(cos θ  bb(1 - sin  θ)`

= `cos θ/(1 - sin θ)` = R.H.S.

∴ L.H.S. = R.H.S.

∴ sec θ + tan θ = `cos θ/(1 - sin θ)`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2025-2026 (March) Model set 3 by shaalaa.com

संबंधित प्रश्‍न

If cot θ = `7/8` evaluate `((1+sin θ )(1-sin θ))/((1+cos θ)(1-cos θ))`.


State whether the following are true or false. Justify your answer.

sin θ = `4/3`, for some angle θ.


In the following, trigonometric ratios is given. Find the value of the other trigonometric ratios.

`sin A = 2/3`


In the following, trigonometric ratios is given. Find the value of the other trigonometric ratios.

`cos A = 4/5`


In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.

`sin theta = sqrt3/2`


if `sec A = 17/8` verify that `(3 - 4sin^2A)/(4 cos^2 A - 3) = (3 - tan^2 A)/(1 - 3 tan^2 A)`


If `cot theta = 3/4`, prove that `sqrt((sec theta - cosec theta)/(sec theta + cosec theta)) = 1/sqrt7`


If `sin theta = a/b` find sec θ + tan θ in terms of a and b.


If `sin θ = 3/4` prove that `sqrt(("cosec"^2θ - cot^2θ)/(sec^2θ - 1)) = sqrt(7)/3`.


Evaluate the Following

`4/(cot^2 30^@) + 1/(sin^2 60^@) - cos^2 45^@`


Find the value of x in the following:

`2 sin  x/2 = 1`


If sin θ + sin² θ = 1, then cos² θ + cos4 θ = ______.


If sin A = `1/2`, then the value of cot A is ______.


If 4 tanθ = 3, then `((4 sintheta - costheta)/(4sintheta + costheta))` is equal to ______.


Find the value of sin 45° + cos 45° + tan 45°.


Find will be the value of cos 90° + sin 90°.


Prove that `tan θ/(1 - cot θ) + cot θ/(1 - tanθ)` = 1 + sec θ cosec θ


If sin θ + cos θ = `sqrt(2)` then tan θ + cot θ = ______.


Evaluate 2 sec2 θ + 3 cosec2 θ – 2 sin θ cos θ if θ = 45°.


(3 sin2 30° – 4 cos2 60°) is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×