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Question
If 4 tanθ = 3, then `((4 sintheta - costheta)/(4sintheta + costheta))` is equal to ______.
Options
`2/3`
`1/3`
`1/2`
`3/4`
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Solution
If 4 tanθ = 3, then `((4 sintheta - costheta)/(4sintheta + costheta))` is equal to `underlinebb(1/2)`.
Explanation:
Given,
4 tanθ = 3
⇒ tanθ = `3/4` ...(i)
∴ `(4 sin theta - cos theta)/(4 sin theta + cos theta) = (4 sin theta/cos theta - 1)/(4 sin theta/cos theta + 1)` ...[Divide by cos θ in both numerator and denominator]
= `(4 tan theta - 1)/(4 tan theta + 1)` ...`[∵ tan theta = sin theta/cos theta]`
= `(4(3/4) - 1)/(4(3/4) + 1)` ...[Put the value from equation (i)]
= `(3 - 1)/(3 + 1)`
= `2/4`
= `1/2`
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Prove that: cot θ + tan θ = cosec θ·sec θ
Proof: L.H.S. = cot θ + tan θ
= `square/square + square/square` ......`[∵ cot θ = square/square, tan θ = square/square]`
= `(square + square)/(square xx square)` .....`[∵ square + square = 1]`
= `1/(square xx square)`
= `1/square xx 1/square`
= cosec θ·sec θ ......`[∵ "cosec" θ = 1/square, sec θ = 1/square]`
= R.H.S.
∴ L.H.S. = R.H.S.
∴ cot θ + tan θ = cosec·sec θ
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