Question

If θ is an acute angle and sin θ = cos θ, find the value of tan² θ + cot² θ – 2.

Answer 1

Given, sin θ = cos θ

`sinθ/cosθ` = 1

tan θ = 45°

`\implies` θ = 45°

So tan² θ + cot² θ – 2 = tan² 45° + cot² 45° – 2

= 1 + 1 – 2

= 0

∴ tan² θ + cot² θ – 2 = 0