Advertisements
Advertisements
प्रश्न
If θ is an acute angle and sin θ = cos θ, find the value of tan2 θ + cot2 θ – 2.
Advertisements
उत्तर
Given, sin θ = cos θ
`sinθ/cosθ` = 1
tan θ = 45°
`\implies` θ = 45°
So tan2 θ + cot2 θ – 2 = tan2 45° + cot2 45° – 2
= 1 + 1 – 2
= 0
∴ tan2 θ + cot2 θ – 2 = 0
APPEARS IN
संबंधित प्रश्न
State whether the following are true or false. Justify your answer.
sin θ = `4/3`, for some angle θ.
In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.
`sin theta = sqrt3/2`
If `cot theta = 1/sqrt3` show that `(1 - cos^2 theta)/(2 - sin^2 theta) = 3/5`
If `sin theta = a/b` find sec θ + tan θ in terms of a and b.
Evaluate the following
sin2 30° + sin2 45° + sin2 60° + sin2 90°
Find the value of x in each of the following :
cos x = cos 60º cos 30º + sin 60º sin 30º
If sin (A − B) = sin A cos B − cos A sin B and cos (A − B) = cos A cos B + sin A sin B, find the values of sin 15° and cos 15°.
3 sin² 20° – 2 tan² 45° + 3 sin² 70° is equal to ______.
Let f(x) = sinx.cos3x and g(x) = cosx.sin3x, then the value of `7((f(π/7) + g(π/7))/(g((5π)/14) + f((5π)/14)))` is ______.
If cosec θ = `("p" + "q")/("p" - "q")` (p ≠ q ≠ 0), then `|cot(π/4 + θ/2)|` is equal to ______.
