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Evaluate the Following: tan260∘+4cos245∘+3sec230∘+5cos290cosec30∘+sec60∘-cot230∘ - Mathematics

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प्रश्न

Evaluate the Following:

`(tan^2 60^@ + 4 cos^2 45^@ + 3 sec^2 30^@ + 5 cos^2 90)/(cosec 30^@ + sec 60^@ - cot^2 30^@)`

योग
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उत्तर

`(tan^2 60^@ + 4 cos^2 45^@ + 3 sec^2 30^@ + 5 cos^2 90)/(cosec 30^@ + sec 60^@ - cot^2 30^@)`   ...(i)

By trigonometric ratios we have

`tan 60^@ = sqrt3     cos 45^@ = 1/sqrt2    sec 30^@ = 2/sqrt3`

`cos 90^@ = 0      cosec  30^@ = 2      sec 60^@ = 2    cot 30^@ = sqrt3`

By substituting above values in (i), we get

`((sqrt3)^2 + 4.(1/sqrt2)^2 + 2 + [2/sqrt3]^2 + 5(0)^2)/(2 + 2sqrt2 (+ sqrt3)^2)`

= `(3 + 4. 1/2 + 3 4/3)/(4 - 3)` 

= `(3 + 2 + 4)/1`

= 9

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अध्याय 10: Trigonometric Ratios - Exercise 10.2 [पृष्ठ ४२]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 10 Trigonometric Ratios
Exercise 10.2 | Q 17 | पृष्ठ ४२

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