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If cos θ = 12/13, show that sin θ (1 – tan θ) = 35/156. - Mathematics

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प्रश्न

If `cos θ = 12/13`, show that `sin θ (1 - tan θ) = 35/156`.

If `cos θ = 12/13`, verify that `sin θ (1 - tan θ) = 35/156`.

योग
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उत्तर

Given: cos θ = `12/13`

To prove: sin θ (1 – tan θ) = `35/156`

Proof: We know, cos θ = `B/H`

where the right-angled triangle’s base is B and its hypotenuse is H. ∠ACB = 8 is achieved by building a right triangle ABC at a right angle to B. 

AB is perpendicular, BC = 12 is base, and AC = 13 is hypotenuse.

According to Pythagoras theorem, we have

AC2 = AB2 + BC2

132 = AB2 + 122

169 = AB2 + 144

169 – 144 = AB2

25 = AB2

AB = `sqrt25`

AB = 5


sin θ = `P/H = 5/13`

So, tan θ = `P/H = 5/12`

Put the values in sin θ (1 – tan θ) to find its value,

sin θ (1 – tan θ) = `15/3 (1 - 5/12)`

= `5/13 xx 7/12`

= `35/156`

Hence Proved.

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अध्याय 10: Trigonometric Ratios - Exercise 10.1 [पृष्ठ २४]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 10 Trigonometric Ratios
Exercise 10.1 | Q 14 | पृष्ठ २४
नूतन Mathematics [English] Class 9 ICSE
अध्याय 17 Trigonometric Ratios
Exercise 17A | Q 20. | पृष्ठ ३६०

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