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प्रश्न
Find the value of x in the following :
`sqrt3 sin x = cos x`
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उत्तर
We have
`sqrt3 sin x = cos x`
Now by cross multiplying we get,
`sqrt3 sin x = cos x``
`=> sin x/cos x = 1/sqrt3`.........(1)
Now we know that
`sin x/cos x = tan x` .......(2)
Therefore from equation (1) and (2)
We get
`tan x = 1/sqrt3` .......(3)
since
`tan 30^2 = 1/sqrt3` ....(4)
Therefore, by comparing equation (3) and (4) we get,
`x = 30^@`
Therefore
`x = 30^@`
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संबंधित प्रश्न
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Prove that sec θ + tan θ = `cos θ/(1 - sin θ)`.
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= `1/square + square/square`
= `square/square` ......`(∵ sec θ = 1/square, tan θ = square/square)`
= `((1 + sin θ) square)/(cos θ square)` ......[Multiplying `square` with the numerator and denominator]
= `(1^2 - square)/(cos θ square)`
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∴ L.H.S. = R.H.S.
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