English

Find the Value Of X In the Following : Square Root 3 Sin X = Cos X

Advertisements
Advertisements

Question

Find the value of x in the following :

`sqrt3 sin x = cos x`

Advertisements

Solution

We have

`sqrt3 sin x = cos x`

Now by cross multiplying we get,

`sqrt3 sin x = cos x``

`=> sin x/cos x = 1/sqrt3`.........(1)

Now we know that

`sin x/cos x = tan x` .......(2)

Therefore from equation (1) and (2)

We get

`tan x = 1/sqrt3` .......(3)

since

`tan 30^2 = 1/sqrt3` ....(4)

Therefore, by comparing equation (3) and (4) we get,

`x = 30^@`

Therefore

`x = 30^@`

shaalaa.com
  Is there an error in this question or solution?
Chapter 10: Trigonometric Ratios - Exercise 10.2 [Page 42]

APPEARS IN

R.D. Sharma Mathematics [English] Class 10
Chapter 10 Trigonometric Ratios
Exercise 10.2 | Q 22 | Page 42

Video TutorialsVIEW ALL [2]

RELATED QUESTIONS

If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.


In the following, one of the six trigonometric ratios is given. Find the values of the other trigonometric ratios.

`tan alpha = 5/12`


In the following, one of the six trigonometric ratios is given. Find the values of the other trigonometric ratios.

`cos theta = 12/2`


If `cos θ = 12/13`, show that `sin θ (1 - tan θ) = 35/156`.


if `cot theta = 3/4` prove that `sqrt((sec theta - cosec theta)/(sec theta +cosec theta)) = 1/sqrt7`


Evaluate the following

sin 45° sin 30° + cos 45° cos 30°


Evaluate the following

`2 sin^2 30^2 - 3 cos^2 45^2 + tan^2 60^@`


Evaluate the Following

(cos 0° + sin 45° + sin 30°)(sin 90° − cos 45° + cos 60°)


Find the value of x in the following :

`sqrt3 tan 2x = cos 60^@ + sin45^@ cos 45^@`


If cos (81 + θ)° = sin`("k"/3 - theta)^circ` where θ is an acute angle, then the value of k is ______.


3 sin² 20° – 2 tan² 45° + 3 sin² 70° is equal to ______.


If sin 2A = `1/2` tan² 45° where A is an acute angle, then the value of A is ______.


If A and (2A – 45°) are acute angles such that sin A = cos (2A – 45°), then tan A is equal to ______.


Prove that: cot θ + tan θ = cosec θ·sec θ

Proof: L.H.S. = cot θ + tan θ

= `square/square + square/square`  ......`[∵ cot θ = square/square, tan θ = square/square]`

= `(square + square)/(square xx square)`  .....`[∵ square + square = 1]`

= `1/(square xx square)`

= `1/square xx 1/square`

= cosec θ·sec θ  ......`[∵ "cosec"  θ = 1/square, sec θ = 1/square]`

= R.H.S.

∴ L.H.S. = R.H.S.

∴ cot θ + tan θ = cosec·sec θ


`sqrt(3)` cos2A + `sqrt(3)` sin2A is equal to ______.


If sin θ + cos θ = `sqrt(2)` then tan θ + cot θ = ______.


Let f(x) = sinx.cos3x and g(x) = cosx.sin3x, then the value of `7((f(π/7) + g(π/7))/(g((5π)/14) + f((5π)/14)))` is ______.


If f(x) = `3cos(x + (5π)/6) - 5sinx + 2`, then maximum value of f(x) is ______.


Evaluate 2 sec2 θ + 3 cosec2 θ – 2 sin θ cos θ if θ = 45°.


(3 sin2 30° – 4 cos2 60°) is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×