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In the Following, Trigonometric Ratios Are Given. Find the Values of the Other Trigonometric Ratios. `Sin Theta = 11/5` - Mathematics

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In the following, trigonometric ratios are given. Find the values of the other trigonometric ratios.

`sin theta = 11/5`

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We know `sin theta = "opposite side"/"hypotenuse" = 11/15`

Consider right-angled Δle ACB

Let x = ЁЭСОЁЭССЁЭСЧЁЭСОЁЭСРЁЭСТЁЭСЫЁЭСб ЁЭСаЁЭСЦЁЭССЁЭСТ

By applying Pythagoras

ЁЭР┤ЁЭР╡2 = ЁЭР┤ЁЭР╢2 + ЁЭР╡ЁЭР╢2

225 = 121+ЁЭСе2

ЁЭСе2 = 225 -121

ЁЭСе2 = 104

`x = sqrt104`

`cos = "adjacent side"/"hypotenuse" = sqrt(104/15)`

`tan = "opposite side"/"adjacent side" = 11/sqrt104`

`cosec theta = 1/sin theta = 15/11`

`sec = 1/cos theta = 15/sqrt104`

`cot = 1/ tan theta = sqrt104/11`

 

 

 

 

 

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рдЕрдзреНрдпрд╛рдп 10: Trigonometric Ratios - Exercise 10.1 [рдкреГрд╖реНрда реирей]

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рдЖрд░рдбреА рд╢рд░реНрдорд╛ Mathematics [English] Class 10
рдЕрдзреНрдпрд╛рдп 10 Trigonometric Ratios
Exercise 10.1 | Q 1.04 | рдкреГрд╖реНрда реирей

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State whether the following are true or false. Justify your answer.

sec A = `12/5` for some value of angle A.


In the following, one of the six trigonometric ratios is given. Find the values of the other trigonometric ratios.

`tan theta = 8/15`


If `cos θ = 12/13`, show that `sin θ (1 - tan θ) = 35/156`.


if `tan theta = 12/13` Find `(2 sin theta cos theta)/(cos^2 theta - sin^2 theta)`


if `cos theta = 3/5`, find the value of `(sin theta - 1/(tan theta))/(2 tan theta)`


if `cot theta = 3/4` prove that `sqrt((sec theta - cosec theta)/(sec theta +cosec theta)) = 1/sqrt7`


Evaluate the following

cos2 30° + cos2 45° + cos2 60° + cos2 90°


Evaluate the Following

(cos 0° + sin 45° + sin 30°)(sin 90° − cos 45° + cos 60°)


Evaluate the Following:

`tan 45^@/(cosec 30^@) + sec 60^@/cot 45^@  - (5 sin 90^@)/(2 cos 0^@)`


The value of sin² 30° – cos² 30° is ______.


5 tan² A – 5 sec² A + 1 is equal to ______.


If sin A = `1/2`, then the value of cot A is ______.


Prove that sec θ + tan θ = `cos θ/(1 - sin θ)`.

Proof: L.H.S. = sec θ + tan θ

= `1/square + square/square`

= `square/square`  ......`(тИ╡ sec θ = 1/square, tan θ = square/square)`

= `((1 + sin θ) square)/(cos θ  square)`  ......[Multiplying `square` with the numerator and denominator]

= `(1^2 - square)/(cos θ  square)`

= `square/(cos θ  square)`

= `cos θ/(1 - sin θ)` = R.H.S.

∴ L.H.S. = R.H.S.

∴ sec θ + tan θ = `cos θ/(1 - sin θ)`


What will be the value of sin 45° + `1/sqrt(2)`?


Prove that: cot θ + tan θ = cosec θ·sec θ

Proof: L.H.S. = cot θ + tan θ

= `square/square + square/square`  ......`[тИ╡ cot θ = square/square, tan θ = square/square]`

= `(square + square)/(square xx square)`  .....`[тИ╡ square + square = 1]`

= `1/(square xx square)`

= `1/square xx 1/square`

= cosec θ·sec θ  ......`[тИ╡ "cosec"  θ = 1/square, sec θ = 1/square]`

= R.H.S.

∴ L.H.S. = R.H.S.

∴ cot θ + tan θ = cosec·sec θ


Let f(x) = sinx.cos3x and g(x) = cosx.sin3x, then the value of `7((f(π/7) + g(π/7))/(g((5π)/14) + f((5π)/14)))` is ______.


If cosec θ = `("p" + "q")/("p" - "q")` (p ≠ q ≠ 0), then `|cot(π/4 + θ/2)|` is equal to ______.


(3 sin2 30° – 4 cos2 60°) is equal to ______.


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